A small steel ball bearing with a mass of 19.0 g is on a short compressed spring. When aimed vertically and suddenly released, the spring sends the bearing to a height of 1.35 m. Calculate the horizontal distance the ball would travel if the same spring were aimed 35.0 deg from the horizontal?

Explanation:

Given,

Mass of the steel = 19 g

height reached, h = 1.35 m

angle, θ = 35°

when the ball is projected vertically with initial velocity v.

Maximum height reached is equal to,

initial velocity,

  v = 5.14 m/s

Hence , the maximum velocity is equal to 5.14 m/s

For projectile motion horizontal distance is given by

the horizontal distance travel by the ball is equal to

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explanation:

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