Using the stress state given in the previous problem determine the traction vector on a plane that makes equal intercept to all the three axis. Also determine the normal stress and the magnitude of shear stress on this plane

not too sure thinking all accelerations are pointed down

initial speed when it is dropped is 150 ft/s

now at the same moment the acceleration due to gravity is perpendicular to its velocity

so as we know that

now we have centripetal acceleration a = 32 ft/s^2 as its perpendicular to velocity

while tangential acceleration at the same moment will be zero

so

now radius of curvature is given as

so the radius of curvature just after it is dropped is 703.125 ft

c) power lifting, will be your answer.

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deku ❤