In a prototype helicopter, a jet is expelled out of the helicopter’s side to make it turn in the opposite direction. If the jet supplies 10,000 N of force and the helicopter’s forward speed remains at 20 m/s, what is the radius of the helicopter’s turn?

The radius is (0.04m) meters

Explanation:

F = mv^2/r

m is the mass of the helicopter = m kg

v is the speed of the helicopter = 20 m/s

F is force supplied by the jet = 10,000 N

10,000 = m×20^2/r

r = 400m/10,000 = 0.04m

The radius is (0.04m) meters

b would be the answer

one person pulls 90n one way and the other has 100n pulling the other way.

so the net force = 90 - 100 = -10n,

or the ans can be 10n if the picture shows -90n and 100n instead.