If a ball's speed increases from 16 m/s to 64 m/s, then its kinetic energy is how many times larger?

The KE becomes 16 times larger

Explanation:

Kinetic energy =

where m = mass  ,  v= velocity.

The velocity of the body increases from 16 m/s to 64 m/s.

v1 =16 m/s  , v2=64 m/s.

The ratio of the final Kinetic to the initial Kinetic energy will give us the required answer

final Kinetic energy / initial Kinetic energy =

=

= 64²/16²

=16 times larger

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