The diagram below depicts a wire, xy, moving through a uniform magnetic field toward point A. The length of the wire is 0.20 meter and the magnetic field strength is 0.50 newton per ampere-meter. The wire moves uniformly at 1.0 meter per second.

What is the magnitude of the induced voltage in wire xy?

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Answerthe energy required is 1.60 × 10⁻¹⁸ j, to three significant figures.explanationwe define electric potential as the ratio electric potential energy to the charge,    then the following gives us the potential difference,      the formula  may be on your formula sheet.the change in electric potential energy would be the energy that would needed to move it from point a to point b. solving for that, we get    using q = 8.00  × 10⁻¹⁹ c and  δv = 2.00 v, we get    the energy required is 1.60 × 10⁻¹⁸ j, to three significant figures.