Two objects form a closed system. One object, which is at 400 K, absorbs 25.0 kJ of heat from the other object, which is at 500 K. What is the net change in entropy ΔSsysΔSsysDeltaS_sys of the system? Assume that the temperatures of the objects do not change appreciably in the process

Explanation:

The given data is as follows.

        = 400 K,     = 500 K,  

= 25 kJ = 25000 J   (as 1 kJ = 1000 J)

Now, we will calculate the change in entropy as follows.

Putting the given values into the above formula as follows.

                      =      

                      = 250 J/K

Hence, we can conclude that change in entropy is 250 J/K.

so easy. just google the electromagnetic waves and it’ll pop up.

the total distance that martina travels that day is

(distance from home to mom's office) plus (distance from mom's office to school)

plus (distance from school to library) plus (distance from library to friend's house)

plus (distance from friend's house to martina's house).

(we don't know what any of these distance actually is.)