Calculate the molar mass of sulfur in a sample that consists of 91.65% 32S (molar mass 31.97 g/mol), 2.4% 33S (molar mass 32.97 g/mol), 5.95% 34S (molar mass 33.97 g/mol). Answer in units of g/mol.

32.11 g/mol

Explanation:

Given;

32S => 91.65%, 31.97g/mol

33S => 2.4%, 32.97g/mol

34S => 5.95%, 33.97g/mol

The molar mass of sulfur in the sample is the weighted average of the molar masses of its isotopes based on the percentage abundances.

i.e

molar mass = ( x 31.97) + ( x 32.97) + ( x 33.97)

molar mass = (0.9165 x 31.97) + (0.024 x 32.97) + (0.0595 x 33.97)

molar mass = (29.30) + (0.79) + (2.02)

molar mass = 32.11g/mol

Therefore the molar mass of sulfur in the sample is 32.11 g/mol

i guess it’s a and b