The velocity of an 11-kg box changes from 5.1 m/s to 15 m/s. How much
total work is done on the box?
O A. 1,100 3
OB. 1,500 3
OC. 2,100 J
OD. 2,500

The total work done on the box will be equal to 1100 J.

Option A

Explanation:

As per work energy theorem, total work done on any object will be equal to the change in kinetic energy of the object.

So change in kinetic energy =

Here, m is the mass, v is the final velocity and u is the initial velocity of the object.

As the mass is given as 11 kg and the final velocity is given as 15 m/s with the initial velocity of the box being 5.1 m/s, then the change in kinetic energy will be as follows.

Kinetic energy = (0.5×11)×()=0.5×11×198.99

Thus, the kinetic energy = 1094 J.

According to the options, this value is nearly equal to 1100 J. Thus, the total work done on the box will be equal to 1100 J.

f is prop to m1xm2 double m1 double force

explanation:

considering the bohr theory, the type of connection that requires the transfer the answer conuldn't be right