A0.9 kg football is thrown with a velocity of 22.0 m/s to the right. a stationary receiver catches the ball and brings it to rest in 0.06 seconds. what is the force exerted on the receiver?

-330 N.

Explanation:

Force is defined as the mass and the acceleration of a body.

The  formula of force is given as,

F = m(v-u)/t Equation 1.

Where m = mass of the football, u = initial velocity of the football, v = final velocity of the football, t = time.

Given: m = 0.9 kg, u = 22.0 m/s, v = 0 m/s ( brought it to rest), t = 0.06 seconds.

Substitute into equation 1,

F = 0.9(0-22)/0.06

F = 0.9(-22/0.06)

F = -330 N.

F = -330 N.

Note: The force is negative because it acts against the the receiver.

it is the second option.

  the grams     of oxygen gas   that can be produced     is 20.6   grams of o₂

calculation

2liclo₃ →   2 licl + 3 o₂

step 1:   find the moles of liclo₃

moles = mass÷ molar mass

from periodic table the molar mass of liclo₃ =6.9 +35.5   +(16 x3) =90.4 g/mol

moles=38.7 g÷90.4 g/mol=0.4281   moles

step 2:   use the   mole ratio   to calculate the moles of o2

from equation above, liclo₃: o₂   is 2: 3  

therefore the moles of   o₂=0.4281 moles x3/2 =0.6422   moles

step 3: find mass   of o₂

mass= moles x molar mass

from periodic table the   molar mass of   o₂ = 16 x2= 32 g/mol

mass=0.6422   moles   x   32 g/mol = 20.6 grams of o₂