0.0387 kg of molten copper at its melting point (1083°c) is poured into a vat of water. how much heat must be removed to cool it to a solid at 22.0°c? (remember, it has to solidify first.) (unit=j)

23901.39 J

Explanation:

Total Thermal Energy removed

= Energy lost to change state from liquid to solid + Energy lost to cool solid from melting pt to 22 C

= mlf + mcT [bolded is for state change, italicised is for cooling solid from melting pt to 22 C]

= (0.0387)(2.07 × 10^5) + (0.0387)(387)(1083 - 22)

= 23901.39 J (2 dp)

be subject to a force andchange its motion