How much heat must be removed from 0.175 kg of water to lower its temperature from 24.3°c to 5.00°c? (unit = j)

14185.5J

Explanation:

Thermal energy can be calculated using the formula

Q = mcT where

Q is the amount of thermal energy in J

m is the mass in kg

c is the specific heat capacity in J/kg/C

T is the change in Temperature in C.

Hence by applying this formula, we get:

Q = (0.175)(4200)(24.3 - 5.00)

Q = 14185.5 J

i think the answer is a, hope this : )

answer: 2×10^-2kg

explanation: density= mass per volume

vol=mass/density

converting to s.i units we have;

3÷1000kg = 0.003

1.5÷100m = 0.15

0.003/0.15 = 0.02kg