Aclamped 24 cm wire with 25 g/m mass density vibrates at its fundamental mode near an 85 cm long open/closed tube. the wire vibration excites the second harmonic of the tube. what is the tension in the wire in n?

T = 518.4 N

Explanation:

Length of wire,l = 24 cm = 0.24 m

mass density of wire,μ = 25 g/m = 0.025 g/m

Length of the tube, L = 85 cm = 0.85 m

speed of sound, v = 340 m/s

frequency in the tube in open/closed tube

now, calculation of tension in the wire.

Frequency in the wire will be same as frequency in the tube

now,

squaring both side and arranging

     T = 518.4 N

hence, the tension in wire is equal to T = 518.4 N

6 cos 34, 6 sin 34 trig

grav potential energy