Aspaceship ferrying workers to moon base i takes a straight-line pat from the earth to the moon, a distance of 384,000km, suppose the spaceship starts from rest and accelerates at 20.0 meter per second squared (m/s2).for the first 15.0min of the trip, and then travels at constant speed until the last 15.0 min, when it slows down at a rate of 20.0 meter per second squared (m/ just coming to rest as it reaches the moon, (a) what is the maximum speed attained? (b) what fraction of the total distance is traveled at constant speed? ? (c) what total time is required for the

95.78125%

18000 m/s

22233.33 seconds

Explanation:

t = Time taken

u = Initial velocity

v = Final velocity

s = Displacement

a = Acceleration

The velocity of the rocket at the end of the first 15 minutes is 18000 m/s which is the maximum speed of the rocket in the complete journey.

Distance traveled while speeding up

Distance traveled while slowing down

Distance traveled during constant speed

Fraction

Fraction of the total distance is traveled at constant speed is 95.78125%

Time taken at constant speed

Total time taken is

the skeletons of most mammals reach a certain size and then stop growing. however, many animals, including some mammals, keep growing throughout their lives. kangaroos, for example, just keep growing and growing until they die. also, the longer an animal lives the greater the chance it might catch some deadly disease.

1.195000

explanation:

total mass=0.0117+0.0137+0.0881+0.0111

total mass= 0.01172kg

total velocity = 0.283-0.743+0.871-0.799+0.155+0.637+0.301=0.102

momentum=mv=0.1172*0.102=1.195000//