Aproton orbits a long charged wire, making 1.80 ×106 revolutions per second. the radius of the orbit is 1.20 cm what is the wire's linear charge density? .

linear charge density = -9.495 × C/m

Explanation:

given data

revolutions per second = 1.80 ×

radius = 1.20 cm

solution

we know that when proton to revolve around charge wire then centripetal force is require to be in orbit of radius around provide by electric force

so

- q × E = m × w² × r     ..................1

- 9 ×  × q =  m × w² × r   ............2

and w =  

w =

w = 1.80 × ×

w = 11304000 rad/s

so here from equation 2

- 9 ×  × 1.80 × =  1.672 × × 11304000² × 0.0120  

linear charge density = -9.495 × C/m

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i hope this you out, have a wonderful day

hello, i am papaguy.

i have found an answer to your question but use it as information.

information: because weak acids/bases have low concentration of hydrogen ions, the addition of water has a large impact on the ph. 2. a difference in 1 unit is a 10x difference in concentration for example; a liquid with ph of 3 is 10x more acidic than a liquid with a ph of 4. therefore, a liquid with a ph of 3 is stronger.

best of luck!