Two point charges of equal magnitude are 7.3 cm apart. at the midpoint of the line connecting them, their combined electric field has a magnitude of 50 n/c .

q₁ = q₂ = Q = 14.8 pC

Explanation:

Given that

q₁ = q₂ = Q = ?

Distance between charges = r =7.3 cm = 0.073 m

Combined electric field = E₁ + E₂ = E = 50 N/C

Using formula

Rearranging for Q

v 154.9= 0.9 length length s little over 154.9cm

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