Two charges (q1 = 3.8*10-6c, q2 = 3.2*10-6c) are separated by a distance of d = 3.25 m. consider q1 to be located at the origin. 2) what is the distance in meters?

The distance is 1.69 m.

Explanation:

Given that,

First charge

Second charge

Distance = 3.25 m

We need to calculate the distance

Using formula of electric field

Put the value into the formula

Hence, The distance is 1.69 m.

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