Astudent creates a circuit that consists of a single battery and four resistors that are arranged as shown. how much energy is dissipated by the 2 ω resistor after 120 s if the total current drawn from the battery is 5 a?

6000JOules

Explanation:

My friend this is quite easy.

There is an equation.

The energy is also presumed as heat.

To calculate the heat in a circuit or the energy the equation is H=I(square) RT

Heat= square of current x resistance x time

Here I=5a.

R=2 ohm

T=120s

H= 5x5x2x120=6000J

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