Ablock of mass 0.454 kg is hung from a vertical spring and allowed to reach equilibrium at rest. as a result, the spring is stretched by 0.662 m. find the spring constant.

Explanation:

For a spring mass system we have

           Mass x Acceleration due to gravity = Spring constant x Elongation

           mg = kl

Mass, m= 0.454 kg

Acceleration due to gravity, g = 9.81 m/s²

Spring constant,k = ?

Elongation, l = 0.662 m

Substituting

           0.454 x 9.81 = k x 0.662

            k = 6.73 N/m

Spring constant is 6.73 N/m

12000j is work done