Avertical spring with spring stiffness constant 305 n/m oscillates with an amplitude of 28.0 cm when 0.235 kg hangs from it. the mass passes through the equilibrium point (y=0) with positive velocity at t=0. positive direction of y-axis is downward.

part a

what equation describes this motion as a function of time?

part b

at what time will the spring stretch to its maximum length at first time?

part c

at what time will the spring shrink to its minimum length at first time?

0.0436 s

0.1308 s

Explanation:

A = Amplitude = 28 cm

m = Mass = 0.235 kg

k = Spring constant = 305 N/m

The equation which describes motion as a function of time is given by

Angular speed is given by

The equation is

Maximum length will be at amplitude

Amplitude is given by

here

The time to stretch to maximum length is 0.0436 s

At minimum length

The time will the spring shrink to its minimum length at first time is 0.1308 s

question1

1,000 tons

question2

3: 8

question 3

store d

step-by-step explanation:

what is the question because that is not a question.