If three of 3 ohms, 5 ohms, and 22 ohms are connected in series in a 28-volt circuit, how much current will flow through the 3-ohm resistor? a - 9.3 amperesb - 1.05 amperesc - 0.93 amperes

Explanation:

We know that in series connection current in all the resistors are same.

Effective resistance is sum of individual resistances.

Here three of 3 ohms, 5 ohms, and 22 ohms are connected in series in a 28-volt circuit

Effective resistance = 3 + 5 + 22 = 30 ohms

Voltage = 28 V

We know

        Voltage = Current x Resistance

         V = IR

         28 = 30 x I

         I = 0.93 A

Current in each resistor is 0.93 A

Option C is the correct answer.

he kicked it 10 feet straight up into the air? i think this works.

the minimum constant speed at which she can catch the train is 2.7 m/s

given:

acceleration = 0.6

time = 4.5 s

to find:

velocity = ?

formula used:

from 1st kinematic equation we get,

v = u + at

u = initial speed of train = 0 m/s

v = final speed of the train

a = acceleration of the train

t = time

solution:

from 1st kinematic equation we get,

v = u + at

u = initial speed of train = 0 m/s

v = final speed of the train

a = acceleration of the train

t = time

v = 0 + (0.6 × 4.5)

v = 2.7 m/s

the minimum constant speed at which she can catch the train is 2.7 m/s