Apowerful motorcycle can accelerate from rest to 24.8 m/s (55 mi/h) in only 5.90 s. (a) what is its average acceleration in m/s? ? m/s² (b) how far does it travel in that time? m

Answer

given,

initial speed,u = 0 m/s

final speed,v = 24.8 m/s

time, t= 5.9 s

a) acceleration,

     a = 4.20 m/s²

b) distance to travel in that time

using equation of motion

   v² = u² + 2 as

   24.8² = 0² + 2 x 4.20 x s

       8.4 s = 615.04

          s = 73.22 m

the motorcycle will travel 73.22 m

anchor = archer //

  distance on the y-axis and time on the x-axis.

explanation:

the instantaneous velocity = change in position/time taken

the slope of the graph should give instantaneous velocity.

  slope of a graph = change in value of y -axis / change in values of x -axis

  comparing both the equations

    change in value of y -axis = change in position

  change in values of x -axis = time taken

so position values should be on the y axis and time values should be on the x axis.

distance on the y-axis and time on the x-axis.