Starting at 1.0 m/s, a cheetah runs with a constant acceleration for 4.8 s reaching a speed of 28 m/s. what is the acceleration of this cheetah? a. 6.5 m/s^2 b. 7.2 m/s^2 c. 5.6 m/s^2 d. 5.8 m/s^2 e. 7.7 m/s^2

c.

Explanation:

Initial velocity of cheetah,u=1 m/s

Time taken by cheetah =4.8 s

Final velocity of cheetah,v=28 m/s

We have to find the acceleration of this cheetah.

We know that

Acceleration,

Where v=Final velocity of object

u=Initial velocity of object

t=Time taken by object

Using the formula

Then, we get

Acceleration, a=

Acceleration=

Hence, the acceleration of cheetah=

f=ma newton

f=100x2.5=250n