Acharge q is transferred from an initially uncharged plastic ball to an identical ball 17 cm away. the force of attraction is then 68nm .
how many electrons were transferred from one ball to the other?

2.92 x 10¹² electrons

Explanation:

given,

distance between two plastic ball, r = 17 cm

                                      r = 0.17 m

Force of attraction = F = 68 mN

                F = 0.068 N

number of electron transferred from one ball to another.

using Coulomb Force equation

q² = 2.1835 x 10⁻¹³

q = 4.67 x 10⁻⁷ C

now, number of electron

e is the charge of electron which is equal to 1.6 x 10⁻¹⁹ C

       N = 2.92 x 10¹² electrons

electrons were transferred from one ball to the other is 2.92 x 10¹²

Field strength is directly proportional to the square of charge. The charge on the given plastic ball is

Where,

- field strength = 68 mN = 0.06 N

- charge

- distance =  17 cm =0.17 m

- constant = 9x10⁹

Put the values in the formula,

Therefore, the charge on the given plastic ball is .

To know more about Coulomb  law:

i would think klcio3

radiation

explanation:

heat is transmitted by radiation