Determine the period of a 1.7-m-long pendulum on the moon, where the free-fall acceleration is 1.624 m/s2. express your answer with the appropriate units.

6.42 s

Explanation:

Period: This can be defined as the time taken for a wave or an oscillating body to complete on oscillation. The S.I unit of period is Second (s).

The period of a simple pendulum is represented as,

T = 2π√(L/g) Equation 1.

Where T = period, L = length of the pendulum, g = acceleration due to gravity. π = pie.

Given: L = 1.7 m, g = 1.624 m/s² and π = 3.14

T = 2(3.14)√(1.7/1.624)

T = 6.28√(1.047)

T = 6.28×1.023

T = 6.42 s.

Thus, the period of the pendulum = 6.42 s

v 154.9= 0.9 length length s little over 154.9cm