Aspiral spring of a spring balance is 25.0cm long when 5n hangs on it and 30.0cm long when the weight is 10n. what is the length of the spring if the weight is 3n, assuming hooked law is charged

it's a b and

96.77 amp

explanation:

rl = 250/100 = 2.5 ohms.

egl = 250 + (100 × 0.1) + 2 = 262 v.

at 700 r.p.m., eg2 = 262 × 700/1000 = 183.4 v.

if ia is the new current, then eg2 - 2 - (ia × 0.1) = 2.5 ia

which means this will give ia = 96.77 amp.