A(n) 19000 kg freight car is rolling along a track at 1.5 m/s. calculate the time needed for a force of 2600 n to stop the car.

10.96secs

Explanation:

According to newton's second law

Force = mass × acceleration

F = ma

F = m(v-u)/t

Cross multiplying we have

Ft = m(v-u)

t = m(v-u)/F

Given F = 2600N m = 19,000kg v = 1.5m/s u = 0m/s

Substituting this values in the formula for the time we have

t = 19000(1.5-0)/2600

t = 28,500/2600

t= 10.96secs

it becomes positively charged by charging it

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