It takes the elevator in a skyscraper 3.6 s to reach its cruising speed of 11 m/s. a 62 kg passenger gets aboard on the ground floor.
what is the passenger's weight before theelevator starts moving?

Weight of the passenger will be 607.6 N

Explanation:

We have given that a elevator takes 3.6 sec to reach its cursing speed

So time t = 3.6 sec

Velocity v = 11 m /sec

Mass of the passenger m = 62 kg

We have to find the weight of the passenger weight before elevator starts moving

Before the elevator starts moving

So weight of the passenger will be equal to

i don't understand is there any other way you can rephrase it plz let me know in the comments and i will do it.

explanation:

1/0.14nm = 10^10/1.4 a lot