Along thin rod of mass m and length l is situated along the y axis with one end at the origin. a small spherical mass m1 is placed at the location p, which is at a distance d from the origin.

if l = 2.00 ? 104 m, d = 18.0 ? 104 m, m = 14.0 ? 106 kg, and m1 = 8.00 ? 106 kg, what is the value of this potential energy?

W= fd
where f is an applied force and d is the distance over which it is applied. when a parachuting skydiver is at constant velocity, he is experiencing "terminal velocity", the point at which his acceleration down is canceled out by air resistance. that means that the resisting force of the air is equal to his weight, but in the opposite direction. with this, we can solve for the work done by the force.
w = fd
w = (92.0)(9.81 m/s^2) (325)
w= 2.93 x 10^5 j
the value for work in this case is positive because it is pushing up on the skydiver, who has a downward force of gravity.
therefore the answer is 2.93 x 10^5 j

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