Question 7 (5 points)
blaine steps onto a ski slope with an angle of 25°. there is a coefficient of kinetic friction of
0.75 between him and the ground. he has a mass of 65 kg.
b. write the expressions for net force in the x and y directions be sure to tilt your axis along the incline
c. calculate the net force and acceleration in the x and y directions

The net force is 165N an the the acceleration is 2.5 m/s2

Explanation: First find the component of force with respect to the angle of inclination.

F = mgsin (theta) = 65 kg x 9.8 m/s2 x sin (25°) = 286N

Next find the value of the normal force

N = mgcos ( theta)

= 65 kg x 9.8m/s² x cos (25°)

= 577N

Substitute the Value of N to find the frictional force.

fk= Coeffiecient of kinetic friction x N

= 0.75x 577 N = 433 N

Solve for the net force through summation of forces.

433 N - 268N = 165N

To find a. Use F= ma

Derive so that a= F/m

a= 165N / 65kg

= 2.54 m/s2

the minimum amperage that the current in this wire would have to have so that its weight is completely supported by the magnetic force due to earth's field, assuming that no other forces except gravity act on it

  distance on the y-axis and time on the x-axis.

explanation:

the instantaneous velocity = change in position/time taken

the slope of the graph should give instantaneous velocity.

  slope of a graph = change in value of y -axis / change in values of x -axis

  comparing both the equations

    change in value of y -axis = change in position

  change in values of x -axis = time taken

so position values should be on the y axis and time values should be on the x axis.

distance on the y-axis and time on the x-axis.