Determine the length of the tungsten filament in a 100 watt lightbulb given: (i) the resistivity of tungsten is 5.6 × 10−8 ω · m, (ii) the filament diameter is 0.0018 inches, and (iii) that the filament temperature is about 2550°c when it is "on". show your work. how is possible to use this length filament in the bulb? explain! hint: assume a ambient temperature of 25°c and an operating voltage of 120vrms (more on this and you will have to look up the temperature coefficient of tungsten to complete the calculations.
Answers: 3
= Resistivity of tungsten = 
= Temperature coefficient of tungsten = 
![R_2=R_1[1+\alpha(T_2-T_1)]\\\Rightarrow R_1=\dfrac{R_2}{1+\alpha(T_2-T_1)}\\\Rightarrow R_1=\dfrac{144}{1+0.0045(2550-25)}\\\Rightarrow R_1=11.64812\ \Omega](/tpl/images/0463/6836/7c1cd.png)
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