During an in-class demonstration of momentum change and impulse, mr. h asks jerome (102 kg) and michael (98 kg) to sit on a large 14-kg skate cart. mr. h asks suzie (44 kg) to sit on a second 14-kg skate cart. the two carts are placed on low friction boards in the hallway. jerome pushes off of suzie's cart. measurements are made to determine that suzie's cart acquired a post-impulse speed of 9.6 m/s. determine the expected recoil speed of jerome and michael's cart.

2.6 m/s

Explanation:

mass of Jerome (Mj) = 102 kg

mass of Micheal (Mm) = 98 kg

mass of each cart (Mc) = 14 kg

recoil speed of Jerone and Micheal after push (Vi) = ?

mass of Suzie (Ms) = 44 kg

Suzie's speed after push (Vs) = 9.6 m/s

From the conservation of momentum, initial momentum = final momentum

Since they all are initially at rest the initial momentum is 0 and hence the final momentum is also 0.

Therefore for the final momentum we have

(Mj + Mm + Mc) Vi - (Ms + Mc) Vs = 0  ( the negative sign is because they move in opposite directions)

((102 + 98 + 14) x Vi ) - ((44 + 14) x 9.6) = 0

(214 x Vi) - (58 x 9.6) = 0

214 Vi = 556.8

Vi = 556.8 / 214 = 2.6 m/s

u=13

v=30

s/t=u+1\2at

=13+431/2

=13+265.5

=278.5

1 the 4 is sig