The charges q1=q and q2=4q that are a distance d apart, repel each other with a force of 1.60 n. what would be the force between the charges q3=2q and q4=7q that are a distance d/3 apart?

50.4 N

Explanation:

Q1 = Q

Q2 = 4 Q

Distance = d

The force is given by

   .... (1)

Now,

Q3 = 2 Q

Q4 = 7 Q

distance = d/3

  .... (2)

Divide equation (2) by equation (1), we get

F' / 1.60 = 126 / 4

F' = 50.4 N

Thus, the force is 50.4 N.

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explanation:

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