Aloudspeaker diaphragm is vibrating in simple harmonic motion with a frequency of 760 hz and a maximum displacement of 0.85 mm.
(a) what is the angular frequency?
(b) what is the maximum speed?
(c) what is the maximum acceleration?

(a) 4775.2Hz (b) 4.06m/s (c) 19382.15m/s²

Explanation: Given that the frequency of oscilation f, is 760Hz and the maximum displacement x, is 0.85mm= 0.00085m

(a) Angular frequency w= 2πf

w= 2π × 760 = 4775.2Hz

(b) Maximum speed v is given as the product of angular frequency and maximum displacement

V=wx

V= 4775.2 × 0.00085

V= 4.06m/s

(c) The maximum acceleration a

= w²x

= (4775.2)² × (0.00085)

a= 19382.15m/s².

1 a

2 b

3 b

4 d

5 d

6 d

explanation: