Aforce of magnitude 25 n and directed at an angle of 37 degrees above the horizontal is used to move a 10 kg crate along a surface at a constant velocity. how much work is done by the force in moving the crate 15 m? a.107 jb.0 jc.98 jd.40 j

To solve this problem we will apply the work theorem. That is, the work can be expressed as the product between the force applied and the distance traveled of the object to perform a given action. Mathematically

W = F*d

In turn, from the definition of Force, we know that according to Newton's second law, it is the product between mass and acceleration. Mathematically

F = ma

Since the acceleration is zero, because the velocity is constant, we will have to

F = m * (0)= 0

Therefore work

W = 0*d cos37

W = 0 J

The correct answer is B.

a 2,000 calorie based diet.

r = ρ x length / area  

ρ = r x area / length  

ρ is in ohm-meters  

in basic units, it is m³kg/s³a²  

i think this is it.