Aparticle with charge 6.40 x 10^—19 c travels in circular orbit with radius 4.68 mm due to the force exerted on it by a magnetic field with magnitude 1.65 t and perpendicular to the orbit. a. what is the magnitude of the linear momentum p of the particle? b. what is the magnitude of the angular momentum l of the particle?

(a)

(b)

Explanation:

In order to find the linear and angular momentum, we should first find the velocity of the particle.

The relationship between force, velocity and magnetic field is

This force is the net force applied to the charge, and by Newton's Second Law:

By combining the two equations:

Now we can calculate the momentum.

(a)

(b)

the current is 0.6

voltage ÷ resistance = current

so 12 ÷ 20 = 0.6

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