A100-n uniform ladder, 8.0 m long, rests against a smooth vertical wall. the coefficient of static friction between ladder and floor is 0.40. what minimum angle can the ladder make with the floor before it slips?

The minimum angle is 51.34°

Explanation:

Given that,

Weight of ladder = 100 N

Length = 8.0 m

Coefficient of static friction = 0.40

We need to calculate the normal force

Using Newtons law in vertical direction

We need to calculate the normal force

Using Newtons law in horizontal direction

We need to calculate the minimum angle

Using torque about the point A then

Put the value into the formula

Hence, The minimum angle is 51.34°

the answer is a)

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