What is the magnitude of the momentum of a 3400 kg airplane traveling at a speed of 400 miles per hour? (note that you need to convert speed to meters per second. a mile is 1600 meters.)

The momentum of the airplane = 604452 kgm/s

Explanation:

Momentum: This can be defined as the product of mass and velocity. The S.I unit of momentum is kgm/s.

Mathematically it is expressed as

M = mv Equation 1

Where, M = momentum of the air plane, m = mass of the airplane, v = velocity of the air plane.

Given: m = 3400 kg, v = 400 miles per hour

Conversion: 400(1600/3600) m/s = 177.78 m/s.

Substituting into equation 1

M = 3400(177.78)

M = 604452 kgm/s.

Thus the momentum of the airplane = 604452 kgm/s

two charges are fixed in place on the x-axis as shown. the charge at x = 0 is negative and has magnitude q = 2 μcoulombs (1 μcoulomb = 10-6 coulombs). the charge at x = d, (d = +12 cm), is positive and has magnitude q = 4 μcoulombs. find a point x = xo along the x-axis at which the electric field is zero.