A3.0-kg mass sliding on a frictionless surface has a velocity of 5.0 m/s east when it undergoes a one-dimensional inelastic collision with a 2.0-kg mass that has an initial velocity of 2.0 m/s west. after the collision the 3.0-kg mass has a velocity of 1.0 m/s east. how much kinetic energy does the two-mass system lose during the collision?

24 J

Explanation:

given,

mass of the block 1, M = 3 Kg

initial speed in east direction, u = 5 m/s

mass of the block 2, m = 2 Kg

initial speed in west direction, u' = 2 m/s

final speed of block 1, after collision, V = 1 m/s

Kinetic energy loss during collision = ?

taking east direction positive

using conservation of momentum

M u + m u' = M V + m V'

3 x 5 + 2 x(-2) = 3 x 1 + 2 x V'

2 x V' = 8

 V' = 4 m/s

loss in kinetic energy

=

=

=

= 24 J

loss in kinetic energy is equal to 24 J

i am pretty sure it is c because when people are closer together, they cannot move as freely. picture being in a mostly full elevator, for instance. the people are right next to you, and you can barely move.

small = small current large mag large current