Physics, 15.01.2020 19:31 kebo63

Which is greater, the force exerted by saturn on the sun or the force exerted by the earth on the sun how much grater

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Answer from: BAJRY

The force exerted by the Earth on the sun is greater than the force exerted by Saturn on the sun by 0.179.

HOW TO CALCULATE THE FORCE EXERTED BY A PLANET ON THE SUN:

The force exerted by a planet on the sun can be calculated using the following formula:

SUN AND SATURN:

F = G m1.m2/r²

Where;

G = gravitational constant (6.67 x 10-¹¹ Nm²/kg²)m1 = mass of sun (1.99 × 10³⁰kg)m2 = mass of Saturn (5.68 × 10²⁶Kg)r = average distance between sun and Saturn (1.5 × 10⁹m)F = 6.67 x 10-¹¹ {1.99 × 10³⁰ × 5.68 × 10²⁶ ÷ (1.5 × 10⁹)²}F = 3.349 × 10²⁸N

SUN AND EARTH:

G = gravitational constant (6.67 x 10-¹¹ Nm²/kg²)m1 = mass of sun (1.99 × 10³⁰kg)m2 = mass of Earth (5.98 × 10²⁴Kg)r = average distance between sun and earth (1.5 × 10⁸m)F = 6.67 x 10-¹¹ {1.99 × 10³⁰ × 5.98 × 10²⁴ ÷ (1.5 × 10⁸)²}F = 3.528 × 10²⁸NThis shows that the force exerted by the Earth on the sun (3.528 × 10²⁸N) is greater than the force exerted by Saturn on the Sun (3.349 × 10²⁸N). The difference between these two forces is calculated as follows:3.528 × 10²⁸N - 3.349 × 10²⁸N= 0.179 or 1.79 × 10-¹

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Answer from: Quest

Centrapedial force is the answer

Answer from: Quest

russian is not my first language, so i'm afraid i can't write out an answer in russian, but hopefully you can find a way to do so. here's my best translation of the problem: you're given a plot of a particle's position in one-dimensional space over time, and you're asked to find either the total distance traveled by the particle after 6 seconds had elapsed, or the total displacement of the particle after 6 seconds.

if you want the total distance traveled, you would first need to determine the particle's velocity as a function of time, then integrate that over the 6-second interval. we know the position function is quadratic with roots at 0 and 6, so we have

$x(t)=ax(x-6)$

where $a$ is unknown. because the position is parabolic, there is symmetry about the midpoint at $t=3$ , and we know that

$x(3)=10\implies -9a=10\implies a=-\dfrac{10}9$

so that the position function is

$x(t)=-\dfrac{10}9x(x-6)$

which means the velocity is

$v(t)=\dfrac{\mathrm dx}{\mathrm dt}=-\dfrac{20}9x+\dfrac{60}9$

then the total distance traveled is

$\displaystyle\int_{t=0}^{t=6}|v(t)|\,\mathrm dt=\left\{\int_{t-0}^{t=3}-\int_{t=3}^{t=6}\right\}v(t)\,\mathrm dt=20$

so the total distance traveled is 20 m.

on the other hand, if you want to find displacement: the particle starts at $x=0$ and ends at $x=0$ , so its displacement is 0.

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