Acubical box 20.00 cm on a side is completely immersed in fluid. at the top of the box the pressure 105.0 kpa at the bottom the pressure is 106.8 kpa. what is the density of the fluid?

ρ = 900 kg/m³

Explanation:

Given that

a= 20 cm

Pressure at the top ,P₁ = 105 KPa

Pressure at the bottom,P₂= 106.8 KPa

Lets take the density of the fluid = ρ kg/m³

The pressure at the bottom given as

P₂ = P₁ + ρ g a

Now by putting the values

106.8 x 1000 = 105 x 1000+ ρ x 10 x 0.2     ( g= 10 m/s²)

1000(106.8 - 105) = 2 ρ

ρ = 900 kg/m³

Therefore the density of the fluid will be 900  kg/m³

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