An object is orbiting at a distance of 10,000km from the center of a planet. the gravitational force between the object and the planet is 10n what would the gravitational force be if the object were orbiting at a distance of 5,000km? (pls show work)

40 N

Explanation:

Gravitational force on an object is:

F = GMm / r²

where G is the universal gravitational constant,

M is the mass of one object (the planet),

m is the mass of the other object,

and r is the distance between the objects.

When r = 10,000 km, F = 10 N.

(10 N) = GMm / (10,000 km)²

GMm = 10⁹ N km²

When r = 5,000 km:

F = (10⁹ N km²) / (5000 km)²

F = 40 N

answer; equivalent to a one(1) horsepower motor;

we have been given a quadratic function and we need to restrict the domain such that it becomes a one to one function.

we know that vertex of this quadratic function occurs at (5,2).

further, we know that range of this function is .

if we restrict the domain of this function to either or , it will become one to one function.

let us know find its inverse.

upon interchanging x and y, we get:

let us now solve this function for y.

hence, the inverse function would be if we restrict the domain of original function to and the inverse function would be if we restrict the domain to .