Aroom is 16 ft x 12 ft x 12 ft. would air enter or leave the room if the temperature changed from 27°c to –3°c while the pressure remained constant? determine the volume of the air which moved in or out of the room.

v= 6.52 m³

convert meter to foot we get

v=230.2 ft³  

Explanation:

Given Data

Room dimension=16ft*12ft*12ft

Temperature changed from 27°c to –3°c

To find

Volume of air

Solution

V(Volume of the room) = 16ft x 12ft x 12ft

V= 2304 ft³

convert foot to meter we get

V=  65.242 m³

R=8.205 × 10⁻⁵ m³ atm / K molGas Constant

Pressure =1 atm  as it remained constant

Initially moles of gas = PV / RT

n= 65.242 / 8.205 × 10⁻⁵ x ( 273 + 27 )

n= 2650.50  

As the temperature changes the new volume for these moles = nRT / P

m= 2650.5 x 8.205 × 10⁻⁵ x ( 273 -3) /1

m=  58.72 m³

So the difference = 65.24 m³ - 58.72 m³

v= 6.52 m³

convert meter to foot we get

v=230.2 ft³

what is the actual question though?

0.93xc=0.93x3x10^8m/s

2.54cm is 1 inch

360seconds i 1 hr