A0.030-m3 container is initially evacuated. then, 4.0 g of water is placed in the container, and, after some time, all the water evaporates. if the temperature of the water vapor is 388 k, what is its pressure?

23895.05 Pa

Explanation:

V = 0.03 m³

mass, m = 4 g

Temperature, T = 388 K

Let P be the pressure.

number of moles, n = 4 / 18 = 0.22

Use ideal gas equation

PV = n RT

P x 0.03 = 0.22 x 8.314 x 388

P = 23895.05 Pa

Thus, the pressure is 23895.05 Pa.

the force required to move the cart is divided by three or 33.33 n.

the chart show the masses and velocities of two colliding objects that stick together after a collision.

according to the law of conservation of momentum, the momentum of the object after the collision is  

answer

1,500

kg • m/s.