A42.0-cm diameter disk rotates with a constant angular acceleration of 2.70 rad/s2. it starts from rest at t = 0, and a line drawn from the center of the disk to a point p on the rim of the disk makes an angle of 57.3° with the positive x-axis at this time.

(a) find the angular speed of the wheel at t=2.30s.

(b) find the linear velocity and tangential acceleration of p at t=2.30s.

(c) find the position of p (in degrees, with respect to the positive x-axis) at t = 2.30s.

6.21 rad/s

1.3041 m/s, 0.567 m/s²

Explanation:

= Final angular velocity

= Initial angular velocity = 0

= Angular acceleration = 2.3 rad/s²

= Angle of rotation

t = Time taken = 2.3 s

Equation of rotational motion

The angular speed is 6.21 rad/s

Linear velocity is given by

Linear velocity is 1.3041 m/s

Tangential acceleration is given by

Tangential acceleration is 0.567 m/s²

In degress the angle would be

From x axis it would be

The angle is from x axis

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