Physics, 09.01.2020 05:31 alvaradorosana05

Not in book

.two positive charges are fixed in place. a 5
.0mc charge is
placed 2m to theleft of the origin and a 3 .0mc charge is
placed1m to the left of the origin. at
what point(s) is theelectric field zero?

Answers: 3

Show answers

Answers

Answer from: Ramone8070

$x=2.4365\ m$

and

$x=-1.4365\ m$

Explanation:

Given:

first charge, $q_1=5\times 10^{-3}\ C$ second charge, $q_2=3\times 10^{-3}\ C$ position of first charge, $x_1=-2\ m$ position of second charge, $x_2=-1\ m$

Now since there are only 2 charges and of the same sign so they repel each other. This repulsion will be zero at some point on the line joining the charges.

Now, according to the condition, electric field will be zero where the effects of field due to both the charges is equal.

E_1=E_2

since first charge is greater than the second charge so we may get a point to the right of the second charge and the distance between the two charges is 1 meter.

$\frac{1}{4\pi.\epsilon_0} \frac{q_1}{(r+1)^2} =\frac{1}{4\pi.\epsilon_0} \frac{q_2}{(r)^2}$

$\frac{5\times 10^{-3}}{(r+1)^2} = \frac{3\times 10^{-3}}{(r)^2}$

3(r^2+1+2r)=5r^2

2r^2-6r-3=0

$r=3.4365 \&\ r=-0.4365$

Since we have assumed that the we may get a point to the right of second charge so we calculate with respect to the origin.

$x=-1+3.4365=2.4365\ m$

and

$x=-1-0.4365=-1.4365\ m$

Answer from: Quest

force is based upon mass and acceleration.the statement is not always true.

it can be explained from newton's second law of motion.

as per newton's second law of motion the rate of change of momentum is directly proportional to the applied force and takes place along the direction of force.

mathematically it can be written as -

$f\alpha \frac{dp}{dt}$

⇒ $f= k \frac{dp}{dt}$

here k is the proportionality constant whose value is 1.

$f=\frac{dp}{dt}$

$f= \frac{d[mv]}{dt}$

$f= m\frac{dv}{dt} +v\frac{dm}{dt}$

$f=ma+v\frac{dm}{dt}$ [a is the acceleration=dv/dt]

hence we see that force not only depends on mass and acceleration but also on velocity and rate of change of mass. force f will depend on mass and acceleration only when mass is constant.

hence the statement that force is based upon mass and acceleration is false.

Answer from: Quest

Domain eukarya; kingdom plantae should be the answer.

Another question on Physics

Physics, 22.06.2019 05:00

Red light strikes a metal surface and electrons are ejected. if violet light is now used with a 10% greater intensity, what will happen to the ejection rate (number of ejected electrons per second) and the maximum energy of the electrons? a) greater ejection rate; same maximum energyb) same ejection rate; greater maximum energyc) greater ejection rate; greater maximum energyd) same ejection rate; same maximum energye) none of the above answers are correct

Answers: 1

Answer

Physics, 22.06.2019 07:30

Identify the theory that can be used to explain each phenomenon. answers diffraction: wave theory interference: wave theory reflection: both particle and wave theories refraction: both particle and wave theories

Answers: 3

Answer

Physics, 22.06.2019 11:20

How to tell if a molecule is polar or nonpolar with electronegativity

Answers: 2

Answer

Physics, 22.06.2019 16:20

The energy equivalent of the rest mass of an electron is

Answers: 1

Answer

You know the right answer?

Not in book

.two positive charges are fixed in place. a 5
.0mc charge is
pla...