Arope, assumed massless is stretched horizontally between
twosupports that are 3.44 m apart. when an object of weight 3160 n
ishung at the center of the rope, the rope is observed to sag by
35.0cm. what is the tension of the rope?

7900N

Explanation:

35cm = 0.35m

When the object is at the rope center, its position at 3.44 / 2 =1.72m. We can find out the angle that the sagged rope makes with the horizontal

this means the rope makes with the vertical an angel of

90 - 11.5= = 78.5 degree

The tension of the 2 ropes, T, should balance with the object weight

= \frac{3160}{2*0.2} = 7900N[/tex]

yup its correct its: c) b b

friction

explanation:

they us to move forward and backwards