Force of 2000n acts on mass of 0.04kg over a distance of 10m. assuming that mass is initially at rest, find the final velocity and time for which the force acts on the body

Data:- F=2000N m=0.04kg s=10m vi=o(mass is initially at rest) to find vf=? and t=?

Explanation:

solution :- F=ma to find acceleration a=f/m ,a=2000/0.04=50000 a=50000m/sec² now find time according second eq of motion s=vit+1/2at², 10=0×t +1/2 50000 ×t² ,10=25000×t² ,t²=10÷25000=0.0004 sq root on bothside

t=0.02sec now find vf so according to first eq of motion vf=vi+at , vf=0+50000×0.02=1000m/sec acceleration=50000m/sec²,t=0.02sec and vf=1000m/s.

most voltage drop calculators want the distance between the source and destination. then internally, they double it so both the source and return wires are calculated. but you need to know which distance the calculator uses so you're not half of what you should be or double what you should be.

most circuit breakers will not take a #6 directly, so the electrician will have to splice on a smaller pigtail. you also have to upsize the grounding wire when you upsized the ungrounded (hot) wire (see note in 250.122). this will preclude using most cable assemblies, as a cable with #6 copper will most likely only have a #10 grounding conductor. you need a #6 grounding conductor if the circuit is 20a. a #8 cable is no better, as it will have a #10 grounding conductor too. but most 20a breakers will take a #8 directly.

in your related post, you didn't say what type of load this is. if it is a light or heater, voltage drop won't be a big issue. if this is a motor, the current needs are huge at startup and the voltage drop can pose a problem. if this is a motor, knowing if the motor is under much load during startup will answer the voltage drop effect (a saw is easier to start than a compressor).

a person with a mass of 106kg has a weight of 1060n