Two long thin parallel wires 13.0 cm apart carry 25-a currents in the same direction.
1. determine the magnitude of the magnetic field vector at a point 10.0 cm from one wire and 6.0 cm from the other.
2. determine the direction of the magnetic field vector at that point.

3.33 x 10⁻⁵ T

Explanation:

given,

current carried by two parallel wire = 25 A

distance between two wire = 13 cm

1) Let p be the distance between two wire

         p = 13 cm = 0.13 m

         a = 10 cm = 0.1 m

         b = 6 cm = 0.06 m

 using cosine law

       θ = 105.96°

       θ = 106°(approximately)

now, magnetic field on one wire

      B₁ = 5 x 10⁻⁵ T

now, magnetic field on another wire

      B₂ = 8.33 x 10⁻⁵ T

resultant field,

=

=

= 3.33 x 10⁻⁵ T

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