A28 kg child goes down a straight slide inclined 38∘ above horizontal. the child is acted on by his weight, the normal force from the slide, kinetic friction, and a horizontal rope exerting a 30 n. how large is the normal force of the slide on the child? if the child slides with a constant speed, how large is the kinetic frictional force from the slide?

The magnitude of the normal force is 197.7 N.

The magnitude of the kinetic frictional force is 192.5 N

Explanation:

Hi!

Please, for a better understanding of the problem, see the attached figure.

We have the following forces acting on the child (see figure):

parallel forces:

Fx = parallel component of the force exerted by the rope, F.

Fr = friction force.

wx = parallel component of the weight.

perpendicular forces:

N = normal force of the slide.

wy = perpendicular component of the weight.

Fy = perpendicular component of the force exerted by the rope, F.

The child does not have an acceleration in the perpendicular direction, then, the sum of forces acting in that direction has to be zero:

N - wy + Fy = 0  (considering upwards as positive)

Solving for N

N = wy - Fy

Using trigonometry of right triangles:

wy = W · cos 38°

wy = m · g · cos 38°

Where m = mass and g = acceleration due to gravity:

wy = 28 kg · 9.8 m/s² · cos 38° = 216.2 N

In the same way, we calculate Fy:

Fy = F · sin 38°

Fy = 30 N · sin 38°

Fy = 18.5 N

Then, the normal force will be:

N = wy - Fy

N = 216.2 N - 18.5 N = 197.7 N

The magnitude of the normal force is 197.7 N

If the child slides with constant speed, the acceleration is zero. That means that the sum of the forces acting in the direction of movement has to be zero:

Fx + wx - Fr = 0

Solving for Fr:

Fr = Fx + wx

And now we proceed in the same way as in the previous question, using trigonometry:

Fx = F · cos 38°

Fx = 30 N · cos 38° = 23.6 N

wx = W · sin 38°

wx = m · g · sin 38°

wx = 28 kg · 9.8 m/s² · sin 38°

wx = 168.9 N

Then Fr will be:

Fr = 23.6 N + 168.9 N = 192.5 N

The magnitude of the kinetic frictional force is 192.5 N

the working equation for the angular size is the product of the physical size and 360 degrees divided by the product of two pi and distance from earth. the minimum size would be 0.559 degrees while the maximum size would be 0.49 degrees. 

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