For small amplitudes of oscillation the motion of a pendulum is simple harmonic. consider a pendulum with a period of 0.550 s find the ground-level energy. express your result in joules find the ground-level energy. express your result in election volts

To solve this problem we will use the concepts related to the expression of energy for harmonic oscillator. From our given values we have that the period is equivalent to

Therefore the frequency will be the inverse of the period and would be given as

The ground state energy of the pendulum is,

The ground state energy in eV,

The energy difference between adjacent energy levels,

air exerts forces on falling objects near earth’s surface.

explanation:

the term 'free falls' refer to object that are falling towards the earth, in a situation in which gravity is the only force acting on the object.

for an object in free fall, the acceleration is constant (g, the gravitational acceleration), and so the velocity of the object constantly increases.

for objects near earth's surface, there is always another force acting on the object: the resistance due to the air. this force is opposed to the direction of fall of the object, and it is proportional to the velocity of the object, so as the object falls down, this force increases up to a point when it balances the force of gravity, and the object continues its motion at constant velocity (called terminal velocity). since in this case gravity is not the only force acting on the object, we are not in a situation of free fall.